Yesterday I played my first game of AH. A question came up regarding monster damage. We were two players vs. Yig. How exactly does the final beast take damage? It’s worded funny. I figured that it went like this: each player rolls all their attack dice, records their total number of successes and it’s divided by the two players to arrive at the number of hit point damage. For example if I rolled three successes, and my other player rolls one, a total of four successes are scored and this divided by the two players come to a total of two hits of damage. He thought that no matter how many successes we scored, as long as we had *at *__ least two__ successes we get

__hit. This made rolling his attack redundant if I get at lease two successes, and that we could only ever score one hit at a time. Also, looking at Cthulhu himself…he regenerates one hit of damage every turn/round…so it would be impossible to take him out (same as some of the others). Then he suggested that perhaps we each roll for hits and apply up to__

*one*__hit of damage each. This didn’t make sense either, because if you were playing with up to five players, each has to get five successes to do one point of damage (impossible in some situations, or for some players). It also conflicted with the way the rule was written, stating that all players__

*one*__their successes and then apply damage.__

*total*So, my question is…do all players total their successes, divide by the number of players and then apply that amount of damage to the monster (be it one, two, or two hundred points of damage) and discard/reset the number to zero before the next round of combat (after dealing with it’s attacks, etc)?