I was playing with Jenny Barnes against Yig. I had a shotgun (each 6 rolled gives me 2 success instead of only one).
I was playing alone (1 player game) and Yig awakened so i was cursed because of his "start of battle" ability.
My stats were: fight 4 and speed 4 (only stats that really matters against him). The shotgun gives me +4 combat dice for a total of 8 dice... against Yig's -3 modifier, i play 5 dice.
In the first round i don't roll to try to lose my curse because it's the following round i earned it (though i'll fail the check in all other rounds and i won't lose my curse for the entire combat).
Playing 5 dice i scored in the first round two 6s (4 successes).
I passed his first attack (speed check) so i don't lose my sanity and stamina in the first round (but i'll fail in all other rounds). I started combat with 4 sanity and 4 stamina.
In the next round i score another two 6s (more 4 successes) and fail his attack check (now i'm with 3/3 sanity/stamina).
In the third and last round of combat (though i'm almost sure i'm wrong) i score one 6 (more 2 success). So i scored 10 successes (1 for each of his doom tokens, Yig has only 10 doom tokens and it's the easiest of all ancient ones to battle). Did i win or i just take 3 doom tokens off? Each round i take one doom token and all other success of the round are discarded?
In the first round for example, i scored 4 success. One success is enough to take his first doom token away because i was playing alone, but all the other 3 are discarded because it resets to 0 each time a player has enough success to take one doom token off? If that's true, it'd be almost impossible to battle Yig alone (and impossible to fight any other ancient one). Because i'd need at least 10 entire rounds to take one of each doom token per round (assuming i'd have at least one success EVERY round O_o).