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Question about the final shootout

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#1 lino_87



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Posted 23 September 2011 - 09:26 PM

"Normal" shootout are quite clear: the one with more dice rolls first a number of dice equal to stregth+cart - (strength of the opponent + cart of the opponent) and after that is a roll each until someone dies.

Can someone explain me the final shootout with an example? I didn't really understand how it works...

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