How do you calculate DoF using the Easy DoS method? Take the 10s digit of your roll and subtract it by the 10s digit of your target number?

Just take the tens digit of your roll. At least if I'm interpreting this right.

If you're rolling a 28, you have 2 DoS. If you roll a 44, you have 4 DoS. If you roll a 5, zero DoS.

All provided that the Test otherwise is still a success, of course. That's the easy thing about this houserule: you literally just take the tens as-is.

I'm tempted to agree that it may not be "psychologically as satisfying" as RAW, but that's really just because we - or at least some people - allow ourselves to get cheated by our brain. I've suggested this to my group, and two people were immediately opposed thinking that'd suck, whilst the 3rd at least acknowledged that "mathematically it'd be the same" but they'd still feel weird. I for one would have loved to give it a try, as I really think this is an ingenious solution to a very small but still unnecessary bit of calculation.

It also leads to really bizarre "Black Knight" moments when a character loses multiple limbs but keeps fighting regardless.

That's why GW's Inquisitor game tracked a total injury score in addition to individual limbs. Solves that issue, but is - again - more bookkeeping.

BI's/FFG's rules also might circumvent this "Black Knight" syndrome by including a risk to die even on limb locations, though.

**Edited by Lynata, 15 June 2014 - 10:51 PM.**